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Proof step 15 from proof fits-law-mod-01 (previous step)

¬(s2i(sho) ≠ 0 ∧ abs(s2i(sho)) ≤ 32767 + 1), 0 < i % s2i(sho), 0 ≤ i, ~32768 ≤ i % s2i(sho), 32767 < i % s2i(sho) ⊦ s2i(sho) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ 0 < abs(i) ↔ i ≠ 0;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ¬ i ≤ j ↔ j < i;