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Proof step 9 from proof fits-law-mod-01 (previous step)

¬(~32768 - 1 ≤ ~ abs(s2i(sho)) ∧ s2i(sho) ≠ 0), i % s2i(sho) < ~32768, i < 0, i % s2i(sho) < 0 ⊦ s2i(sho) = 0, i % s2i(sho) = s2i(i2s(i % s2i(sho)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ 0 < abs(i) ↔ i ≠ 0;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i - j ≤ i0 ↔ i ≤ j + i0;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;%i < 0 ⊦ (* i) + j = j - ~ i;% ⊦ i ≤ ~ j ↔ i + j ≤ 0;