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Proof step 15 from proof fits-law-mod (previous step)

0 < i % b2i(by1), 0 ≤ i, ~128 ≤ i % b2i(by1), 127 < i % b2i(by1) ⊦ i % b2i(by1) = b2i(i2b(i % b2i(by1))), b2i(by1) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: j ≠ 0 ⊦ abs(j) ≤ i0 + 1 → ¬ i0 < i % j subst: [j, i, i0] → [b2i(by1), i, 127] rotate: F spec: int-div inst: name: mod-nls-06

Additional information

Used simplifier rules: byte-ngr-01: ⊦ ¬ 128 < abs(b2i(by));% ⊦ ¬ i ≤ j ↔ j < i; Used terms: b2i(by1), i, 127