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Proof step 4 from proof fits-law-mod (previous step)

¬(~128 ≤ i % b2i(by1) ∧ i % b2i(by1) ≤ 127) ⊦ b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1))), ¬ i % b2i(by1) < ~128 ∧ ¬ 127 < i % b2i(by1)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;