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Proof step 6 from proof fits-law-mod (previous step)

i < 0 ⊦ b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1))), ¬ i % b2i(by1) < ~128 ∧ ¬ 127 < i % b2i(by1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
i % b2i(by1) < ~128, i < 0, i % b2i(by1) < 0 ⊦ b2i(by1) = 0, i % b2i(by1) = b2i(i2b(i % b2i(by1)))

Rule argument

Additional information

Used simplifier rules: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ i < 0 ∧ j ≠ 0 → ¬ 0 < i % j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)