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Proof step 20 from proof fits-law-mul (previous step)

32768 ≤ b2i(by1) * b2i(by2), 0 < b2i(by1) * b2i(by2), 0 ≤ b2i(by1) * b2i(by2) ⊦ b2i(by1) * b2i(by2) = s2i(i2s(b2i(by1) * b2i(by2)))

User applied rule cut formula

And obtained the following new goals

Proof step 21:
32768 = 256 * 128, 32768 ≤ b2i(by1) * b2i(by2), 0 < b2i(by1) * b2i(by2), 0 ≤ b2i(by1) * b2i(by2) ⊦ b2i(by1) * b2i(by2) = s2i(i2s(b2i(by1) * b2i(by2)))

Rule argument

fma: 32768 = 256 * 128

Additional information

Used formulas: 32768 = 256 * 128