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Proof step 24 from proof fits-law-mul (previous step)

¬(b2i(by1) ≤ 256 ∧ b2i(by2) < 128 ∧ 256 ≠ 0 ∧ 0 ≤ b2i(by1) ∧ 0 ≤ b2i(by2)), 256 * 128 ≤ b2i(by1) * b2i(by2), 0 < b2i(by1) * b2i(by2), 0 ≤ b2i(by1) * b2i(by2) ⊦ b2i(by1) * b2i(by2) = s2i(i2s(b2i(by1) * b2i(by2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: byte-ngr: i ≥ 127 ⊦ ¬ (* i) < b2i(by);%byte-nge: i ≥ 128 ⊦ ¬ (* i) ≤ b2i(by);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i * j = j * i;