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Proof step 32 from proof fits-law-mul (previous step)

¬(b2i(by1) < 0 ∧ b2i(by2) < 0 ∧ ~256 ≤ b2i(by1) ∧ ~128 < b2i(by2)), ~256 * ~128 ≤ b2i(by1) * b2i(by2), b2i(by1) < 0, b2i(by2) < 0 ⊦ b2i(by1) * b2i(by2) = s2i(i2s(b2i(by1) * b2i(by2)))

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: byte-ls-256: ⊦ ¬ b2i(by) < ~256;%byte-min: ⊦ b2i(by) ≤ ~128 ↔ b2i(by) = ~128;%byte-nle-02: i < ~128 ⊦ ¬ b2i(by) ≤ (* i);% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ 0 < i ∧ j < 0 → ((* i) * i0 ≤ (* j) ↔ i0 ≤ (j + 1 - i) / i);% ⊦ i + (* j) ≤ (* j0) ↔ i ≤ j0 - j;%i < 0 ⊦ j ≤ (* i) * i0 ↔ ~ i * i0 + j ≤ 0;% ⊦ i < 0 → (0 < i * j ↔ j < 0);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i < 0 → (0 ≤ i * j ↔ j ≤ 0);% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i * j = j * i;