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Proof step 9 from proof fits-law-mul (previous step)

0 < b2i(by1) ∧ b2i(by2) < 0, b2i(by1) * b2i(by2) < ~32768 ⊦ b2i(by1) * b2i(by2) = s2i(i2s(b2i(by1) * b2i(by2)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
b2i(by1) * b2i(by2) < ~32768, 0 < b2i(by1), b2i(by2) < 0 ⊦ b2i(by1) * b2i(by2) = s2i(i2s(b2i(by1) * b2i(by2)))

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)