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Proof step 6 from proof fits-law-neg (previous step)

¬ n→i(# int2bits(~ b2i(by))) ≤ 16 ⊦ b2i(by) + cast(16, ~ b2i(by)) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
16 < # int2bits(~ b2i(by)) ⊦ b2i(by) + cast(16, ~ b2i(by)) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;%0 ≤ i ⊦ n→i(n) ≤ (* i) ↔ n ≤ i→n(i);