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Proof step 32 from proof fits-law-shr (previous step)

0 ≤ b2i(by) ∧ 0 < band(i, 31) ∧ band(i, 31) < 32 ⊦ b2i(by) / 2 ^ band(i, 31) = b2i(i2b(b2i(by) / 2 ^ band(i, 31)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
band(i, 31) < 32, 0 ≤ b2i(by), 0 < band(i, 31) ⊦ b2i(by) / 2 ^ band(i, 31) = b2i(i2b(b2i(by) / 2 ^ band(i, 31)))

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)