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Proof step 2 from proof fits-law-sub (previous step)

⊦ b2i(by1) = s2i(i2s(b2i(by1) - b2i(by2))) + b2i(by2)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ~32768 ≤ i ∧ i < 32768 → s2i(i2s(i)) = i
Proof step 4:
¬(~32768 ≤ b2i(by1) - b2i(by2) ∧ b2i(by1) - b2i(by2) < 32768) ⊦ b2i(by1) = s2i(i2s(b2i(by1) - b2i(by2))) + b2i(by2)

Rule argument

name: short-inrange rotate: F subst: [i] → [b2i(by1) - b2i(by2)]

Additional information

Used simplifier rules: byte-equal: ⊦ b2i(byi) = b2i(byj) ↔ byi = byj;% ⊦ i + (j - i) = j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: b2i(by1) - b2i(by2)