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Proof step 5 from proof fits-law-sub (previous step)

⊦ b2i(by1) = s2i(i2s(b2i(by1) - b2i(by2))) + b2i(by2), ¬ 32768 + b2i(by1) < b2i(by2) ∧ ¬ b2i(by2) + 32768 ≤ b2i(by1)

User applied rule case distinction

And obtained the following new goals

Proof step 6:
⊦ ¬ 32768 + b2i(by1) < b2i(by2), b2i(by1) = s2i(i2s(b2i(by1) - b2i(by2))) + b2i(by2)
Proof step 9:
⊦ ¬ b2i(by2) + 32768 ≤ b2i(by1), b2i(by1) = s2i(i2s(b2i(by1) - b2i(by2))) + b2i(by2)

Rule argument

pos: right 2

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