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Proof step 15 from proof getsetShort-theorem (previous step)

¬(0 ≤ j ∧ 0 ≤ 8), ~32768 ≤ j, j ≤ 32767, ub2i(i2b(j)) < 256, 0 ≤ ub2i(i2b(j)) ⊦ ub2i(i2b(j)) + 256 * b2i(i2b(j >> 8)) = j, (j >> 8)∈byte

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
j < 0, 0 ≤ ub2i(i2b(j)), ub2i(i2b(j)) < 256, ~32768 ≤ j ⊦ ub2i(i2b(j)) + 256 * b2i(i2b(j >> 8)) = j, (j >> 8)∈byte

Rule argument

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%zero-gels-03: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs