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Proof step 18 from proof getsetShort-theorem (previous step)

j < 0 ∧ 8 ≤ 8, j < 0, 0 ≤ ub2i(i2b(j)), ub2i(i2b(j)) < 256, ~32768 ≤ j ⊦ ub2i(i2b(j)) + 256 * b2i(i2b((j - 255) / 256 >> (8 - 8))) = j, ((j - 255) / 256 >> (8 - 8))∈byte

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
j < 0, 0 ≤ ub2i(i2b(j)), ub2i(i2b(j)) < 256, ~32768 ≤ j ⊦ 256 * b2i(i2b((j - 255) / 256)) + ub2i(i2b(j)) = j, ((j - 255) / 256)∈byte

Rule argument

Additional information

Used simplifier rules: rightshift-zero: ⊦ i >> 0 = i; from specification intops