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Proof step 21 from proof getsetShort-theorem (previous step)

i < ~255, ub2i(i2b(i + 255)) < 256, ~33023 ≤ i, i < 0, 0 ≤ ub2i(i2b(i + 255)) ⊦ 256 * b2i(i2b(i / 256)) + ub2i(i2b(i + 255)) = i + 255, (i / 256)∈byte

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 22:
⊦ i ∈byte ↔ ~128 ≤ i ∧ i ≤ 127
Proof step 23:
i < ~255, ub2i(i2b(i + 255)) < 256, ~33023 ≤ i, i < 0, 0 ≤ ub2i(i2b(i + 255)) ⊦ 256 * b2i(i2b(i / 256)) + ub2i(i2b(i + 255)) = i + 255, ~128 ≤ i / 256 ∧ i / 256 ≤ 127

Rule argument

spec: inst: name: inbyte seq: ⊦ i ∈byte ↔ ~128 ≤ i ∧ i ≤ 127 subst: [i] → [i / 256] flags: rewrite, current

Additional information

Used terms: i / 256