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Proof step 30 from proof getsetShort-theorem (previous step)

i0 < ~128, abs(j) < 256, i0 * 256 + j ≤ ~256, ub2i(i2b(j + 255)) < 256, (~128 - i0) * 256 + ~255 ≤ j, i0 < 0, j ≤ 0, i0 * 256 + j < 0, 0 ≤ ub2i(i2b(j + 255)) ⊦ ub2i(i2b(j + 255)) + 256 * b2i(i2b(i0)) = (i0 * 256 + j) + 255

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 31:
i0 < 0, j ≤ 0, i0 * 256 + j < 0, 0 ≤ ub2i(i2b(j + 255)), i0 < ~128, abs(j) < 256, i0 * 256 + j ≤ ~256, ub2i(i2b(j + 255)) < 256, (~128 - i0) * 256 ≤ 255 + j ⊦ ub2i(i2b(j + 255)) + 256 * b2i(i2b(i0)) = (i0 * 256 + j) + 255

Rule argument

Additional information

Used simplifier rules: sub-le: ⊦ i - j ≤ i0 ↔ i ≤ j + i0; from specification int-abs%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%minus-add: i < 0 ⊦ (* i) + j = j - ~ i; from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2