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Proof step 32 from proof getsetShort-theorem (previous step)

~128 = i + i0, i0 < 0, j ≤ 0, i0 * 256 + j < 0, 0 ≤ ub2i(i2b(j + 255)), i0 < ~128, abs(j) < 256, i0 * 256 + j ≤ ~256, ub2i(i2b(j + 255)) < 256, i * 256 ≤ 255 + j ⊦ ub2i(i2b(j + 255)) + 256 * b2i(i2b(i0)) = (i0 * 256 + j) + 255

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pos: left 1 flags:

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