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Proof step 34 from proof getsetShort-theorem (previous step)

0 < i, ~128 = i + i0, i0 < 0, j ≤ 0, i0 * 256 + j < 0, 0 ≤ ub2i(i2b(j + 255)), i0 < i + i0, abs(j) < 256, i0 * 256 + j ≤ ~256, ub2i(i2b(j + 255)) < 256, i * 256 ≤ 255 + j ⊦ ub2i(i2b(j + 255)) + 256 * b2i(i2b(i0)) = (i0 * 256 + j) + 255

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
~128 = i + i0, i0 < 0, j ≤ 0, i0 * 256 + j < 0, 0 ≤ ub2i(i2b(j + 255)), abs(j) < 256, i0 * 256 + j ≤ ~256, ub2i(i2b(j + 255)) < 256, i * 256 ≤ 255 + j, 0 < i, j < i ⊦ ub2i(i2b(j + 255)) + 256 * b2i(i2b(i0)) = (i0 * 256 + j) + 255

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%add-less: ⊦ 0 < i → i1 < i1 + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2