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Proof step 41 from proof getsetShort-theorem (previous step)

j < 32767 + 1, ub2i(i2b(j)) < 256, 0 ≤ ub2i(i2b(j)), 0 ≤ j ⊦ 256 * b2i(i2b(j / 256)) + ub2i(i2b(j)) = j, (j / 256)∈byte

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information