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Proof step 51 from proof getsetShort-theorem (previous step)

(j i>> 8)∈byte, ~32768 ≤ j, j ≤ 32767, ub2i(i2b(j)) < 256, 0 ≤ ub2i(i2b(j)) ⊦ ub2i(i2b(j)) + 256 * (j i>> 8) = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 52:
~32768 ≤ j, j ≤ 32767, ub2i(i2b(j)) < 256, ~128 ≤ j i>> 8, j i>> 8 ≤ 127, 0 ≤ ub2i(i2b(j)) ⊦ ub2i(i2b(j)) + 256 * (j i>> 8) = j

Rule argument

Additional information

Used simplifier rules: inbyte: ⊦ i ∈byte ↔ ~128 ≤ i ∧ i ≤ 127;%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs