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Proof step 63 from proof getsetShort-theorem (previous step)

j / 256 = i + 1, 0 ≤ ub2i(i2b(j)), j < 0, ~32768 ≤ j, ub2i(i2b(j)) < 256, ~128 ≤ i, i ≤ 127 ⊦ j % 256 = 0, ub2i(i2b(j)) + 256 * i = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 64:
⊦ b2i(by) < 0 → ub2i(by) = 256 + b2i(by)
Proof step 65:
¬ b2i(i2b(j)) < 0, j / 256 = i + 1, 0 ≤ ub2i(i2b(j)), j < 0, ~32768 ≤ j, ub2i(i2b(j)) < 256, ~128 ≤ i, i ≤ 127 ⊦ j % 256 = 0, ub2i(i2b(j)) + 256 * i = j
Proof step 70:
b2i(i2b(j)) < 0, j / 256 = i + 1, 0 ≤ 256 + b2i(i2b(j)), j < 0, ~32768 ≤ j, 256 + b2i(i2b(j)) < 256, ~128 ≤ i, i ≤ 127 ⊦ j % 256 = 0, (256 + b2i(i2b(j))) + 256 * i = j

Rule argument

spec: inst: name: ubyte-neg seq: ⊦ b2i(by) < 0 → ub2i(by) = 256 + b2i(by) subst: [by] → [i2b(j)] flags: rewrite, current

Additional information

Used terms: i2b(j)