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Proof step 75 from proof getsetShort-theorem (previous step)

j < 0 ∧ j % 256 = 0, j < 0, 0 ≤ ub2i(i2b(j)), j / 256 ≤ 127, ~128 ≤ j / 256, ub2i(i2b(j)) < 256, ~32768 ≤ j ⊦ ub2i(i2b(j)) + 256 * j / 256 = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 76:
j % 256 = 0, j / 256 ≤ 127, ~128 ≤ j / 256, ub2i(i2b(j)) < 256, ~32768 ≤ j, j < 0, 0 < ub2i(i2b(j)) ⊦ ub2i(i2b(j)) = 0

Rule argument

Additional information

Used simplifier rules: forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%eq: ⊦ i = i + j ↔ j = 0; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%divmult: j ≠ 0 ⊦ i % j = 0 → i / j * j = i; from specification int-div