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Proof step 87 from proof getsetShort-theorem (previous step)

¬ 0 ≤ b2i(i2b(j)), j ≤ 32767, ub2i(i2b(j)) < 256, ~128 ≤ j / 256, j / 256 ≤ 127, 0 ≤ ub2i(i2b(j)), 0 ≤ j ⊦ ub2i(i2b(j)) + 256 * j / 256 = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 88:
b2i(i2b(j)) < 0, ~256 ≤ b2i(i2b(j)), j / 256 ≤ 127, ~128 ≤ j / 256, j ≤ 32767, 0 ≤ j, 128 ≤ j, 0 < j ⊦ 256 * (j / 256 + 1) + b2i(i2b(j)) = j

Rule argument

Additional information

Used simplifier rules: ubyte-neg: ⊦ b2i(by) < 0 → ub2i(by) = 256 + b2i(by);%bib-ls-same-01: ⊦ b2i(i2b(i)) < i ↔ 128 ≤ i;%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%numle-02: ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0; from specification int-abs%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%numls-03: ⊦ i + (* j) < (* j0) ↔ i < j0 - j; from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%succ-rmerge: ⊦ i * j + i = i * (j + 1); from specification int-mult%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs