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Proof step 90 from proof getsetShort-theorem (previous step)

0 ≤ b2i(i2b(j)), j ≤ 32767, b2i(i2b(j)) < 256, ~128 ≤ j / 256, j / 256 ≤ 127, 0 ≤ b2i(i2b(j)), 0 ≤ j ⊦ b2i(i2b(j)) + 256 * j / 256 = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 91:
j ≤ 32767, b2i(i2b(j)) < 256, ~128 ≤ j / 256, j / 256 ≤ 127, 0 ≤ j, 0 ≤ b2i(i2b(j)) ⊦ b2i(i2b(j)) + 256 * j / 256 = j

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs