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Proof step 4 from proof inshort-sis (previous step)

¬(~32768 ≤ i ∧ i ≤ 32767) ⊦ ~32768 ≤ i ∧ i ≤ 32767 ↔ s2i(i2s(i)) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
s2i(i2s(i)) = i, i < ~32768, i < 0 ⊦

Rule argument

Additional information

Used simplifier rules: short-max-10: ⊦ 32767 < i → s2i(sho) ≠ i;% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ ¬ i ≤ j ↔ j < i;