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Proof step 13 from proof long-automatic (previous step)

j < 0 ∨ 9223372036854775807 < j % 18446744073709551616, i % 18446744073709551616 = (0 ≤ j ∧ j % 18446744073709551616 ≤ 9223372036854775807 ⊃ j % 18446744073709551616 ;(0 ≤ j ∧ 9223372036854775807 < j % 18446744073709551616 ⊃ j % 18446744073709551616 - 18446744073709551616 ;(j < 0 ∧ j % 18446744073709551616 < ~9223372036854775808 ⊃ 18446744073709551616 + j % 18446744073709551616 ;(j < 0 ∧ ~9223372036854775808 ≤ j % 18446744073709551616 ⊃ j % 18446744073709551616;j) ) ) ), i % 18446744073709551616 ≤ 9223372036854775807, 0 ≤ i ⊦ i % 18446744073709551616 = (¬ j < 0 ∧ ¬ j % 18446744073709551616 ≤ 9223372036854775807 ⊃ j % 18446744073709551616 - 18446744073709551616 ;(¬ 0 ≤ j ∧ ¬ ~9223372036854775808 ≤ j % 18446744073709551616 ⊃ j % 18446744073709551616 + 18446744073709551616 ;(¬ 0 ≤ j ∧ ¬ j % 18446744073709551616 < ~9223372036854775808 ⊃ j % 18446744073709551616;j) ) )

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ i - j = i0 ↔ i = i0 + j;% ⊦ ¬ i ≤ j ↔ j < i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j;