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Proof step 3 from proof long-eq (previous step)

⊦ i2l(cast(64, i)) = i2l(j) ↔ cast(64, i) = cast(64, j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i2l(i) = i2l(cast(64, i))
Proof step 5:
⊦ i2l(cast(64, i)) = i2l(cast(64, j)) ↔ cast(64, i) = cast(64, j)

Rule argument

name: long-is-cast-01 rotate: F subst: [i] → [j]

Additional information

Used terms: j