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Proof step 3 from proof long-is-cast-01 (
previous step
)
l2i(i2l(i)) = l2i(i2l(cast(64, i))) ⊦ i2l(l2i(i2l(i))) = i2l(l2i(i2l(cast(64, i)))), i2l(i) = i2l(cast(64, i))
User applied rule insert equation
And closed the goal!
Rule argument
pos: left 1 flags: rotate, discard
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