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Proof step 4 from proof long-is-cast-01 (previous step)

⊦ l2i(i2l(i)) = l2i(i2l(cast(64, i))), i2l(i) = i2l(cast(64, i))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ l2i(i2l(i)) = cast(64, i)
Proof step 6:
⊦ cast(64, i) = l2i(i2l(cast(64, i))), i2l(i) = i2l(cast(64, i))

Rule argument

name: long-is-cast rotate: F subst: [i] → [i]

Additional information

Used terms: i