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Proof step 21 from proof long-is-cast (previous step)

64 < # int2bits(i) ⊦ l2i(i2l(cast(n→i(64), i))) = cast(64, i), i ∈long

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
64 < # int2bits(i) ⊦ l2i(i2l(cast(64, i))) = cast(64, i), i ∈long

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)