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Proof step 21 from proof long-shiftzero-in (previous step)

l2i(lo) < 0, 0 < >>>(64, l2i(lo), band(j, 63)), 9223372036854775807 < >>>(64, l2i(lo), band(j, 63)) ⊦ band(j, 63) ≤ 0, ¬ 64 < # int2bits(l2i(lo)) ∧ ¬ band(j, 63) ≤ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ m < n → n ≠ 0; (forward)% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ band(i, j) = band(j, i);% ⊦ ¬ i ≤ j ↔ j < i;