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Proof step 10 from proof mod-inshort (previous step)

0 < s2i(sho0) % s2i(sho1), 32767 < s2i(sho0) % s2i(sho1) ⊦ s2i(sho1) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j
Proof step 12:
¬(s2i(sho1) ≤ 32767 ∧ 0 < s2i(sho1)), 0 < s2i(sho0) % s2i(sho1), 32767 < s2i(sho0) % s2i(sho1) ⊦ s2i(sho1) = 0

Rule argument

spec: int-div inst: name: mod-nls-01 seq: ⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j subst: [j, i, i0] → [s2i(sho1), s2i(sho0), 32767] flags: rewrite

Additional information

Used terms: s2i(sho1), s2i(sho0), 32767