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Proof step 5 from proof mod-inshort (previous step)

⊦ s2i(sho1) = 0, ¬ s2i(sho0) % s2i(sho1) < ~32768 ∧ ¬ 32767 < s2i(sho0) % s2i(sho1)

User applied rule case distinction

And obtained the following new goals

Proof step 6:
⊦ ¬ s2i(sho0) % s2i(sho1) < ~32768, s2i(sho1) = 0
Proof step 9:
⊦ ¬ 32767 < s2i(sho0) % s2i(sho1), s2i(sho1) = 0

Rule argument

pos: right 2

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