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Proof step 2 from proof num-i2l-neg (previous step)

i < ~9223372036854775808 ⊦ i2l(i) = i2l(bits2int(lastn(64, int2bits(i))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i < ~9223372036854775808, i < 0 ⊦ i2l(i) = i2l(bits2int(lastn(64, int2bits(i))))

Rule argument

Additional information

Used simplifier rules: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)