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Proof step 7 from proof num-i2l-neg (previous step)

¬ 64 < # int2bits(i), i < ~9223372036854775808, i < 0 ⊦ i2l(cast(64, i)) = i2l(bits2int(lastn(64, int2bits(i))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
i < ~9223372036854775808, i < 0, # int2bits(i) ≤ 64 ⊦ i2l(cast(64, i)) = i2l(bits2int(lastn(64, int2bits(i))))

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m < n ↔ n ≤ m;