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Proof step 2 from proof num-i2s-pos (previous step)

32767 < i ⊦ i2s(i) = i2s(bits2int(lastn(16, int2bits(i))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < i, 32767 < i ⊦ i2s(i) = i2s(bits2int(lastn(16, int2bits(i))))

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)