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Proof step 1 from proof s2i-switch (conclusion)

⊦ ~32768 ≤ i ∧ i < 32768 → (s2i(sho) = i ↔ sho = i2s(i))

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: isi: ⊦ i2s(s2i(sho)) = sho;%short-inrange: ⊦ ~32768 ≤ i ∧ i < 32768 → s2i(i2s(i)) = i;