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Proof step 2 from proof shiftright-byte-8-neg-01 (previous step)

8 ≤ j, b2i(by) < 0, 0 < j, 0 ≤ j ⊦ b2i(by) >> j = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i < 0 ∧ 8 ≤ j → i >> j = (i - 255) / 256 >> (j - 8)
Proof step 4:
b2i(by) < 0 ∧ 8 ≤ j, 8 ≤ j, b2i(by) < 0, 0 < j, 0 ≤ j ⊦ (b2i(by) - 255) / 256 >> (j - 8) = ~1

Rule argument

seq: ⊦ i < 0 ∧ 8 ≤ j → i >> j = (i - 255) / 256 >> (j - 8) subst: [j, i] → [j, b2i(by)] rotate: F spec: intops inst: name: shiftright-rec-8-neg

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: j, b2i(by)