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Proof step 2 from proof shiftright-byte-8-pos-01 (previous step)

8 ≤ j, 0 ≤ b2i(by), 0 < j, 0 ≤ j ⊦ b2i(by) >> j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i ∧ 0 ≤ j → i >> j = i / 2 ^ j
Proof step 4:
0 ≤ b2i(by) ∧ 0 ≤ j, 8 ≤ j, 0 ≤ b2i(by), 0 < j, 0 ≤ j ⊦ b2i(by) / 2 ^ j = 0

Rule argument

seq: ⊦ 0 ≤ i ∧ 0 ≤ j → i >> j = i / 2 ^ j subst: [j, i] → [j, b2i(by)] rotate: F spec: intops inst: name: shiftright-pos-div

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ i < j → ¬ j < i; Used terms: j, b2i(by)