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Proof step 5 from proof shiftright-byte-8-pos-01 (previous step)

0 ≤ j, 0 < j, 0 ≤ b2i(by), 8 ≤ j ⊦ b2i(by) / 2 ^ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
abs(i) < abs(j) ⊦ i / j = 0
Proof step 7:
¬ abs(b2i(by)) < abs(2 ^ j), 0 ≤ j, 0 < j, 0 ≤ b2i(by), 8 ≤ j ⊦ b2i(by) / 2 ^ j = 0

Rule argument

seq: abs(i) < abs(j) ⊦ i / j = 0 subst: [j, i] → [2 ^ j, b2i(by)] rotate: F spec: int-div inst: name: div-zero-02

Additional information

Used terms: 2 ^ j, b2i(by)