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Proof step 1 from proof short-011x-neg (conclusion)

⊦ s2i(sho) < 0 → band(s2i(sho), 65535) = s2i(sho) + 65536

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
s2i(sho) < 0 ⊦ band(s2i(sho), 65535) = s2i(sho) + 65536

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)