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Proof step 9 from proof short-011x-neg (previous step)

¬ abs(s2i(sho) + 1) < 65536, s2i(sho) < 0 ⊦ (s2i(sho) + 1) % 65536 = 1 + s2i(sho)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
s2i(sho) ≤ ~65537, s2i(sho) < 0 ⊦ (s2i(sho) + 1) % 65536 = 1 + s2i(sho)

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j;% ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;% ⊦ ~ i < j ↔ 0 < j + i;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ ~ i - j = ~(i + j);% ⊦ i < 0 → abs(i) = ~ i;% ⊦ i < 0 → abs(i + 1) = abs(i) - 1;