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Proof step 1 from proof short-32767 (conclusion)

⊦ 32766 < s2i(sho) ↔ s2i(sho) = 32767

User applied rule case distinction

And obtained the following new goals

Proof step 2:
32766 < s2i(sho) ⊦ s2i(sho) = 32767

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)