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Proof step 3 from proof short-32767 (previous step)

0 < s2i(sho), 32766 < s2i(sho) ⊦ s2i(sho) = 32767

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i < j ↔ i +1 = j ∨ i +1 < j

Rule argument

seq: ⊦ i < j ↔ i +1 = j ∨ i +1 < j subst: [j, i] → [s2i(sho), 32766] rotate: F spec: int-basic1 inst: name: lsrec

Additional information

Used simplifier rules: short-ngr: ⊦ ¬ 32767 < s2i(sho); Used terms: s2i(sho), 32766