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Proof step 3 from proof short-add-max-01 (previous step)

s2i(sho1) < 0, 0 < s2i(sho0) + s2i(sho1), 32767 < s2i(sho0) + s2i(sho1) ⊦ 32767 < s2i(sho0) + 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i + j = j + i
Proof step 5:
s2i(sho1) < 0, 0 < s2i(sho0) + s2i(sho1), 32767 < s2i(sho0) + s2i(sho1) ⊦ 32767 < 0 + s2i(sho0)

Rule argument

seq: ⊦ i + j = j + i subst: [j, i] → [0, s2i(sho0)] rotate: F spec: int-basic2 inst: name: add-c

Additional information

Used terms: 0, s2i(sho0)