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Proof step 1 from proof short-add-min (conclusion)

⊦ s2i(sho0) + s2i(sho1) ≤ ~65536 ↔ s2i(sho0) = ~32768 ∧ s2i(sho1) = ~32768

User applied rule case distinction

And obtained the following new goals

Proof step 2:
s2i(sho0) + s2i(sho1) ≤ ~65536 ⊦ s2i(sho0) = ~32768 ∧ s2i(sho1) = ~32768

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;