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Proof step 3 from proof short-add-pos-01 (
previous step
)
⊦ s2i(sho) + s2i(sho0) ≤ 32767 ∧ 0 ≤ s2i(sho) ∧ 0 ≤ s2i(sho0) → s2i(i2s(s2i(sho) + s2i(sho0))) = s2i(sho) + s2i(sho0)
Lemma
short-add-pos