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Proof step 1 from proof short-add-pos (conclusion)

⊦ s2i(sho) + s2i(sho0) ≤ 32767 ∧ 0 ≤ s2i(sho) ∧ 0 ≤ s2i(sho0) → s2i(i2s(s2i(sho) + s2i(sho0))) = s2i(sho) + s2i(sho0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
s2i(sho) + s2i(sho0) ≤ 32767, 0 ≤ s2i(sho), 0 ≤ s2i(sho0) ⊦ s2i(i2s(s2i(sho) + s2i(sho0))) = s2i(sho) + s2i(sho0)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)