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Proof step 1 from proof short-div-ngr (conclusion)

⊦ j ≠ 0 → ¬ 65536 ≤ s2i(sho) / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
65536 ≤ s2i(sho) / j, 0 < s2i(sho) / j, 0 ≤ s2i(sho) / j ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)